diketahui barisan bilangan 4,9,14,19,24 jumlah 14 suku pertama barisan tersebut adalah??
Un=a+(n-1)b
U14=4+(14-1)5
U14=4+13x5
U14=69
Sn=n/2(U1+Un)
S14=14/2(4+69)
S14=7x73
S14=511
Like yaaa
Jawaban:
511
Penjelasan dengan langkah-langkah:
- beda (b) = 9 - 4 = 5. || 24 - 19 = 5.
- suku pertama (a)! = 4
Sn = ½n(2a + (n - 1)b
S14 = ½14 (2(4) + (14 - 1)5
S14 = 14 × (8 + 13(5))/2
S14 = 14 × (8 + 65)/2
S14 = 14 × 73/2
S14 = 1.022/2
S14 = 511
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~℘₊˚✧ οΎ
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